Fix Bug #519: [门诊医生站-诊断-报卡] 已完成传染病报卡的诊断在再次点保存时重复弹出报卡界面

根因:handleInfectiousDiseaseReport() 仅根据诊断名称匹配传染病,未校验该诊断是否已有已提交的报卡记录。

修复方案:
1. 后端 DiagnosisQueryDto 新增 hasInfectiousReport 字段
2. getEncounterDiagnosis SQL 通过 EXISTS 子查询关联 infectious_card 表,
   判断是否存在 status >= 1(已提交/已审核/已上报)的报卡记录
3. 前端 handleInfectiousDiseaseReport() 过滤掉 hasInfectiousReport === 1 的诊断,不再弹出报卡

Co-Authored-By: Claude Opus 4.7 <noreply@anthropic.com>
This commit is contained in:
关羽
2026-05-14 16:15:51 +08:00
committed by 赵云
parent 3e53cb7e67
commit 26f7211eb0
3 changed files with 16 additions and 5 deletions

View File

@@ -96,4 +96,9 @@ public class DiagnosisQueryDto {
*/
private String diagnosisDoctor;
/**
* 是否已有传染病报卡0-无1-有)
*/
private Integer hasInfectiousReport;
}

View File

@@ -134,7 +134,11 @@
T2.yb_no,
T1.onset_date AS onsetDate,
T1.diagnosis_time AS diagnosisTime,
T1.doctor AS diagnosisDoctor
T1.doctor AS diagnosisDoctor,
CASE WHEN EXISTS (
SELECT 1 FROM infectious_card T4
WHERE T4.diag_id = T2.id AND T4.delete_flag = '0' AND T4.status >= 1
) THEN 1 ELSE 0 END AS hasInfectiousReport
FROM adm_encounter_diagnosis AS T1
LEFT JOIN cli_condition AS T2 ON T2.ID = T1.condition_id
AND T2.delete_flag = '0' AND T2.tcm_flag = 0

View File

@@ -692,6 +692,7 @@ async function handleFoodDiseasesCheck() {
/**
* 传染病报告卡处理
* 通过诊断名称自动识别并勾选传染病报告卡中的疾病
* 修复 Bug #519跳过已有已提交报卡的诊断
*/
function handleInfectiousDiseaseReport() {
// 疾病名称到报卡编码的映射(根据传染病报告卡弹窗中的疾病列表)
@@ -743,8 +744,9 @@ function handleInfectiousDiseaseReport() {
'手足口病': '0311',
};
// 获取所有诊断名称对应的报卡编码
// 获取所有诊断名称对应的报卡编码,但跳过已有已提交报卡的诊断
const allSelectedDiseases = form.value.diagnosisList
.filter(d => d.name && d.hasInfectiousReport !== 1)
.map(d => diseaseNameToCode[d.name] || null)
.filter(code => code);
@@ -752,9 +754,9 @@ function handleInfectiousDiseaseReport() {
return;
}
// 优先使用主诊断
const mainDiagnosis = form.value.diagnosisList.find(d => d.maindiseFlag === 1);
const firstDiagnosis = form.value.diagnosisList[0];
// 优先使用主诊断(同样跳过已有报卡的)
const mainDiagnosis = form.value.diagnosisList.find(d => d.maindiseFlag === 1 && d.hasInfectiousReport !== 1);
const firstDiagnosis = form.value.diagnosisList.find(d => d.hasInfectiousReport !== 1) || form.value.diagnosisList[0];
const diagnosisToShow = {
...(mainDiagnosis || firstDiagnosis),