117 lines
4.0 KiB
SQL
117 lines
4.0 KiB
SQL
-- 详细检查诊疗项目检索问题
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-- 已知：wor_activity_definition 表中有4条数据
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-- 1. 检查这4条诊疗项目定义的详细信息
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SELECT
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id,
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name,
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bus_no,
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delete_flag,
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tenant_id,
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create_time
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FROM wor_activity_definition
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ORDER BY id;
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-- 2. 检查收费项目中是否有诊疗项目类型的记录
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-- 注意：ChargeItemContext.ACTIVITY.getValue() 返回的是 Integer 3
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-- 但数据库中 context_enum 可能是字符串类型，需要检查是 '3' 还是 3
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SELECT
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COUNT(*) as total_activity_charge_items,
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COUNT(CASE WHEN delete_flag = '0' THEN 1 END) as active_activity_charge_items,
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COUNT(CASE WHEN delete_flag != '0' THEN 1 END) as deleted_activity_charge_items
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FROM adm_charge_item
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WHERE context_enum::text = '3' OR context_enum = 3; -- 诊疗项目类型是3
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-- 3. 检查收费项目中的product_id是否能匹配到诊疗项目定义
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-- 注意：诊疗项目类型的 context_enum = 3（ChargeItemContext.ACTIVITY.getValue()）
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SELECT
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aci.id as charge_item_id,
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aci.encounter_id,
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aci.context_enum,
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aci.product_id as charge_product_id,
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aci.status_enum,
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aci.delete_flag as charge_delete_flag,
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wad.id as activity_def_id,
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wad.name as activity_name,
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wad.delete_flag as activity_delete_flag,
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CASE
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WHEN wad.id IS NULL THEN '❌ 诊疗项目定义不存在'
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WHEN wad.delete_flag != '0' THEN '❌ 诊疗项目定义已删除'
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WHEN aci.delete_flag != '0' THEN '❌ 收费项目已删除'
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ELSE '✅ 正常'
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END as match_status
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FROM adm_charge_item aci
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LEFT JOIN wor_activity_definition wad
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ON aci.product_id = wad.id
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WHERE (aci.context_enum::text = '3' OR aci.context_enum = 3) -- 诊疗项目类型是3
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LIMIT 20;
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-- 4. 检查context_enum的所有可能值（确认诊疗项目的枚举值是什么）
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SELECT DISTINCT
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context_enum,
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COUNT(*) as count
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FROM adm_charge_item
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WHERE delete_flag = '0'
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GROUP BY context_enum
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ORDER BY context_enum;
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-- 5. 检查是否有收费项目，但无法匹配到诊疗项目定义
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SELECT
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COUNT(*) as unmatched_count,
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STRING_AGG(DISTINCT CAST(product_id AS VARCHAR), ', ') as unmatched_product_ids,
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STRING_AGG(DISTINCT CAST(id AS VARCHAR), ', ') as unmatched_charge_item_ids
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FROM adm_charge_item aci
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WHERE (aci.context_enum::text = '3' OR aci.context_enum = 3) -- 诊疗项目类型是3
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AND aci.delete_flag = '0'
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AND NOT EXISTS (
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SELECT 1
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FROM wor_activity_definition wad
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WHERE wad.id = aci.product_id
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AND wad.delete_flag = '0'
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);
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-- 6. 检查具体某个就诊的诊疗项目（如果有具体的encounterId）
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-- SELECT
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-- T1.encounter_id,
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-- T1.id as charge_item_id,
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-- T1.context_enum,
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-- T1.product_id,
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-- T1.status_enum,
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-- T1.delete_flag,
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-- T2.id as activity_def_id,
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-- T2.name as activity_name,
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-- T2.delete_flag as activity_delete_flag
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-- FROM adm_charge_item AS T1
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-- LEFT JOIN wor_activity_definition AS T2
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-- ON T1.product_id = T2.id
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-- WHERE T1.encounter_id = :encounterId -- 替换为实际的encounterId
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-- AND T1.context_enum IN ('ACTIVITY', '1', 'ACTIVITY_CODE') -- 尝试多种可能的值
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-- AND T1.delete_flag = '0';
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-- 7. 检查后端代码中使用的context_enum值
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-- ChargeItemContext.ACTIVITY.getValue() 的实际返回值需要查看枚举类
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-- 可能是：'ACTIVITY', '1', 'ACTIVITY_CODE', 或其他值
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-- 建议先运行查询4，查看数据库中实际使用的context_enum值
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-- 8. 检查status_enum的值（查询条件中需要匹配的状态）
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-- SQL查询中要求 status_enum IN (1, 2, 3, 4, 5, 6)
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-- 检查收费项目中的状态值是否在这个范围内
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SELECT
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status_enum,
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COUNT(*) as count,
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CASE
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WHEN status_enum IN (1, 2, 3, 4, 5, 6) THEN '✅ 在查询范围内'
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ELSE '❌ 不在查询范围内'
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END as status_check
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FROM adm_charge_item
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WHERE context_enum IN (
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SELECT DISTINCT context_enum
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FROM adm_charge_item
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WHERE delete_flag = '0'
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LIMIT 10
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)
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AND delete_flag = '0'
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GROUP BY status_enum
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ORDER BY status_enum;
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