挂号补单功能的完善

This commit is contained in:
2026-01-14 10:12:25 +08:00
parent 8e61490005
commit d8c4348341
8 changed files with 423 additions and 32 deletions

104
check_display_order.sql Normal file
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-- 检查流水号display_order是否按“科室+医生+当天”正确递增
--
-- 说明:
-- 1. display_order 存的是纯数字1, 2, 3...),不带时间戳前缀
-- 2. 时间戳前缀(如 20260109是在前端显示时加上的
-- 3. 后端用 Redis key "ORG-{科室ID}-DOC-{医生ID}" 按天自增
--
-- 如何判断逻辑是否正确:
-- 同一科室、同一医生、同一天的记录display_order 应该递增1, 2, 3...
-- 不同科室、不同医生、不同天的记录,可能都是 1这是正常的
-- ========================================
-- 查询1按“科室+医生+日期”分组,看每组内的 display_order 是否递增
-- ========================================
SELECT
DATE(start_time) AS ,
organization_id AS ID,
registrar_id AS ID,
COUNT(*) AS ,
MIN(display_order) AS ,
MAX(display_order) AS ,
STRING_AGG(display_order::text, ', ' ORDER BY start_time) AS ,
STRING_AGG(id::text, ', ' ORDER BY start_time) AS ID列表
FROM adm_encounter
WHERE delete_flag = '0'
AND start_time >= CURRENT_DATE - INTERVAL '7 days' -- 只看最近7天
AND display_order IS NOT NULL
GROUP BY DATE(start_time), organization_id, registrar_id
ORDER BY DESC, ID, ID;
-- ========================================
-- 查询2详细查看每条记录看同组内的序号是否连续
-- ========================================
SELECT
id AS ID,
DATE(start_time) AS ,
organization_id AS ID,
registrar_id AS ID,
start_time AS ,
display_order AS ,
-- 计算:同组内的序号应该是 1, 2, 3...,看是否有重复或跳号
ROW_NUMBER() OVER (
PARTITION BY DATE(start_time), organization_id, registrar_id
ORDER BY start_time
) AS ,
CASE
WHEN display_order = ROW_NUMBER() OVER (
PARTITION BY DATE(start_time), organization_id, registrar_id
ORDER BY start_time
) THEN '✓ 正常'
ELSE '✗ 异常'
END AS
FROM adm_encounter
WHERE delete_flag = '0'
AND start_time >= CURRENT_DATE - INTERVAL '7 days'
AND display_order IS NOT NULL
ORDER BY DATE(start_time) DESC, organization_id, registrar_id, start_time;
-- ========================================
-- 查询3只看今天的数据最直观
-- ========================================
SELECT
id AS ID,
organization_id AS ID,
registrar_id AS ID,
start_time AS ,
display_order AS
FROM adm_encounter
WHERE delete_flag = '0'
AND DATE(start_time) = CURRENT_DATE
AND display_order IS NOT NULL
ORDER BY organization_id, registrar_id, start_time;
-- ========================================
-- 查询4发现问题 - 找出同组内 display_order 重复的记录
-- ========================================
WITH ranked AS (
SELECT
id,
DATE(start_time) AS reg_date,
organization_id,
registrar_id,
start_time,
display_order,
ROW_NUMBER() OVER (
PARTITION BY DATE(start_time), organization_id, registrar_id
ORDER BY start_time
) AS should_be_order
FROM adm_encounter
WHERE delete_flag = '0'
AND start_time >= CURRENT_DATE - INTERVAL '7 days'
AND display_order IS NOT NULL
)
SELECT
reg_date AS ,
organization_id AS ID,
registrar_id AS ID,
COUNT(*) AS ,
STRING_AGG(id::text || '->' || display_order::text, ', ') AS
FROM ranked
WHERE display_order != should_be_order
GROUP BY reg_date, organization_id, registrar_id
ORDER BY reg_date DESC;