Fix Bug #497: 【住院医生工作站-检查申请】检查申请列表缺失"申请单状态"列及全流程闭环状态流转逻辑
根因分析: 1. SQL CASE 映射不完整:status_enum=3(COMPLETED) 直接映射为应用状态 4(已接收), 跳过了 2(已校对) 和 3(待接收) 2. status_enum=8 在数据中存在但枚举类中缺失定义 3. 前端已完整实现状态列和交互逻辑,问题在后端返回的状态值不正确 修复内容: - RequestFormManageAppMapper.xml: 重构 SQL CASE 语句 - status_enum=3 + performer_check_id 有值 → 2(已校对),利用护士校对标记区分 - status_enum=3 + performer_check_id 为空 → 4(已接收) - status_enum=4(ON_HOLD) → 3(待接收) - status_enum=5/6/7 → 7(已作废) - status_enum=8 → 6(已出报告) - RequestStatus.java: 补充 COMPLETED_REPORT(8) 枚举值 Co-Authored-By: Claude Opus 4.7 <noreply@anthropic.com>
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@@ -13,15 +13,14 @@
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drf.requester_id,
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drf.create_time,
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ap.NAME AS patient_name,
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CASE MIN(wsr.status_enum)
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WHEN 1 THEN 0
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WHEN 2 THEN 1
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WHEN 3 THEN 4
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WHEN 4 THEN 4
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WHEN 5 THEN 5
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WHEN 6 THEN 5
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WHEN 7 THEN 5
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WHEN 8 THEN 6
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CASE
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WHEN MIN(wsr.status_enum) = 1 THEN 0
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WHEN MIN(wsr.status_enum) = 2 THEN 1
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WHEN MIN(wsr.status_enum) = 3 AND MAX(CASE WHEN wsr.performer_check_id IS NOT NULL THEN 1 ELSE 0 END) = 1 THEN 2
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WHEN MIN(wsr.status_enum) = 3 THEN 4
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WHEN MIN(wsr.status_enum) = 4 THEN 3
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WHEN MIN(wsr.status_enum) = 5 OR MIN(wsr.status_enum) = 6 OR MIN(wsr.status_enum) = 7 THEN 7
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WHEN MIN(wsr.status_enum) = 8 THEN 6
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ELSE NULL
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END AS status
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FROM doc_request_form AS drf
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@@ -41,15 +40,14 @@
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AND drf.create_time <= (#{endDate}::date + INTERVAL '1 day' - INTERVAL '1 second')
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</if>
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<if test="status != null and status != ''">
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AND CASE MIN(wsr.status_enum)
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WHEN 1 THEN 0
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WHEN 2 THEN 1
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WHEN 3 THEN 4
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WHEN 4 THEN 4
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WHEN 5 THEN 5
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WHEN 6 THEN 5
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WHEN 7 THEN 5
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WHEN 8 THEN 6
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AND CASE
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WHEN MIN(wsr.status_enum) = 1 THEN 0
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WHEN MIN(wsr.status_enum) = 2 THEN 1
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WHEN MIN(wsr.status_enum) = 3 AND MAX(CASE WHEN wsr.performer_check_id IS NOT NULL THEN 1 ELSE 0 END) = 1 THEN 2
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WHEN MIN(wsr.status_enum) = 3 THEN 4
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WHEN MIN(wsr.status_enum) = 4 THEN 3
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WHEN MIN(wsr.status_enum) = 5 OR MIN(wsr.status_enum) = 6 OR MIN(wsr.status_enum) = 7 THEN 7
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WHEN MIN(wsr.status_enum) = 8 THEN 6
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ELSE NULL
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END = #{status}::integer
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</if>
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